114 - Flatten Binary Tree to Linked List
Details
| Key | Value |
|---|---|
| Link | https://leetcode.com/problems/flatten-binary-tree-to-linked-list/ |
| Language | Python 3 |
| Runtime | 57 ms, faster than 57.57% of Python3 online submissions for Flatten Binary Tree to Linked List |
| Memory Usage | 15.3 MB, less than 11.27% of Python3 online submissions for Flatten Binary Tree to Linked List |
| Datastructures | Stack, TreeNode |
| Algorithms | Iterate + Stack |
| Complexity | Time: O(N) Memory: O(N) |
Procedure
- ...
Code
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def flatten(self, root: Optional[TreeNode]) -> None:
"""
Do not return anything, modify root in-place instead.
"""
if not root: return
stack, dummy = [root], ListNode(0)
while stack:
node = stack.pop()
if node.right: stack.append(node.right)
if node.left: stack.append(node.left)
dummy.left, dummy.right = None, node
dummy = dummy.right